# TTM Squeeze histogram bar count in label

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I am wondering if a label can be created that counts the number of bars in the lower study, TTM Squeeze, based on  the histogram colors.  Say that the last 2 bars are Cyan color (positive and up per the histogram), the label would read 2 with the background color being Cyan. Next label would show the average number of Cyan bars in a row after the crossover occurred. The length of the periods could be say last 30 bars, or 60, really whatever the number we specify.

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Asked on January 18, 2023 2:27 pm
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 ▲ 0 ▼ ✔ Private answer Since you are asking for a chart label I moved your question out of the "Alerts and Notifications" topic and into the "Chart Studies" topic. I also updated the title of your question to help other viewers locate this post using the search function. I only allocate 15 minutes to each free solution I provide in this forum. Within that time I was just barely able to complete the section that counts bars and displays that in a chart label. The rest of your request is well beyond the complexity of solutions I can provide free of charge in this forum. Here is the solution which adds a label to the chart which shows the color of the current bar and the number of consecutive bar in the current color: ```input price = CLOSE; input length = 20; input nK = 1.5; input nBB = 2.0; input alertLine = 1.0; def squeezeHistogram = TTM_Squeeze(price, length, nK, nBB, alertLine).Histogram; def sqzCyan = squeezeHistogram >= 0 and squeezeHistogram > squeezeHistogram[1]; def sqzBlue = squeezeHistogram >=0 and squeezeHistogram < squeezeHistogram[1]; def sqzRed = squeezeHistogram <= 0 and squeezeHistogram < squeezeHistogram[1]; def sqzYellow = squeezeHistogram <= 0 and squeezeHistogram > squeezeHistogram[1]; rec countCyan = if !sqzCyan then 0 else if sqzCyan and !sqzCyan[1] then 1 else if sqzCyan then countCyan[1] + 1 else countCyan[1]; rec countBlue = if !sqzBlue then 0 else if sqzBlue and !sqzBlue[1] then 1 else if sqzBlue then countBlue[1] + 1 else countBlue[1]; rec countRed = if !sqzRed then 0 else if sqzRed and !sqzRed[1] then 1 else if sqzRed then countRed[1] + 1 else countRed[1]; rec countYellow = if !sqzYellow then 0 else if sqzYellow and !sqzYellow[1] then 1 else if sqzYellow then countYellow[1] + 1 else countYellow[1]; def consecutiveBars = Max(countCyan, Max(countBlue, Max(countRed, countYellow))); AddLabel(yes, Concat("Count: ", consecutiveBars), if sqzCyan then Color.CYAN else if sqzBlue then Color.BLUE else if sqzRed then Color.RED else if sqzYellow then Color.YELLOW else Color.CURRENT);``` Marked as spam Posted by Pete Hahn (Questions: 37, Answers: 3957) Answered on January 18, 2023 3:33 pm Amazing work. Please email me cost to develop rest of the code if possible. (TomSki at January 18, 2023 3:48 pm) If you are interested in paying for a professional quality solution you will find all of those details explained on the following webpage: https://www.hahn-tech.com/about/ (Pete Hahn at January 18, 2023 3:51 pm)